Question

Sodium hydroxide reacts wih excess hydrochloric acid. Calculale the mass of sodium hydroxide required to produce 117g of sodium chloride.​

Answer 1

$\huge\mathfrak\blue{Answer:-}$

Mass of sodium hydroxide will be 57g

Answer 2

Explanation:

NaOH + HCl → NaCl + H2O

1 mole - - - - - - - 1 mole

Molar mass of NaOH = 23+16+1 =40g/mol

Molar mass of NaCl = 23+35.5 =58.5g/mol

To produce 58.5g NaCl 40g NaOH is required

So, to produce 117g NaCl {(40/58.5)×117}g = 80g NaOH is required.

Hope, this helps.