Sodium hypochlorite, NaOCl, is the active ingredient in household bleach. What is the concentration of hypochlorite ion if 20.00 mL of bleach requires 28.30 mL of 0.500 M HCl to reach the equivalence point?
Answers
Answer:
Explanation : Given,
Concentration of HCl = 0.500 M
Volume of HCl = 25.30cm^3=25.30mL=0.2530L25.30cm
3
=25.30mL=0.2530L
conversion used : \begin{gathered}1cm^3=1mL\\1mL=0.001L\end{gathered}
1cm
3
=1mL
1mL=0.001L
Volume of hypochlorite ion = 20.00cm^3=20.00mL=0.2000L20.00cm
3
=20.00mL=0.2000L
The chemical reaction will be:
OCl^-+H^+\rightarrow HClOOCl
−
+H
+
→HClO
First we have to calculate the moles of H^+H
+
ion.
\text{Moles of }H^+=\text{Concentration of }H^+\times \text{Volume of }H^+Moles of H
+
=Concentration of H
+
×Volume of H
+
\text{Moles of }H^+=0.500M\times 0.2530L=0.1265molMoles of H
+
=0.500M×0.2530L=0.1265mol
From the reaction we conclude that,
Moles of H^+H
+
= Moles of ClO^-ClO
−
= 0.1265 mol
Now we have to calculate the concentration of hypochlorite ion.
\text{Moles of }ClO^-=\text{Concentration of }ClO^-\times \text{Volume of }ClO^-Moles of ClO
−
=Concentration of ClO
−
×Volume of ClO
−
0.1265mol=\text{Concentration of }ClO^-\times 0.2000L0.1265mol=Concentration of ClO
−
×0.2000L
\text{Concentration of }ClO^-=0.632MConcentration of ClO
−
=0.632M
Therefore, the concentration of hypochlorite ion is 0.632 M.
Answer:
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