Chemistry, asked by vandu1334, 10 months ago

Sodium iodate is treated with calculated amount of sodium bisulphite to prepare iodine. How many moles of sodium bisulphate is required to prepare one mole of iodine from sodium iodate?

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Answered by Anonymous
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Answer:

sodium thiosulfate iodine sodium iodide sodium tetrathionate. A1.1.2 Reagent preparation. The preferred water for this method should .....

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