Question

Sodium iodide and silver nitrate net ionic equation

Answer 1

Ag+(aq) + I- (aq) --> AgI (s)

NaI + AgNO3 = NaNO3 + AgI

Answer 2

The reaction between sodium iodide and silver nitrate is a double displacement reaction in which the silver iodide is formed as the precipitate with sodium nitrate in the solution.

The balance chemical equation can be written as:

$\mathrm{Nal}+\mathrm{AgNO}_{3} \rightarrow \mathrm{AgI}+\mathrm{NaNO}_{3}$

The ionic equation can be written as:

$\begin{aligned} N a^{+}(a q)+I^{-}(a q)+A g^{+}(a q)+N O_{3}^{-}(a q) & \rightarrow & A g I(s)+N a^{+}(a q)+N O_{3}^{-}(a q) \end{aligned}$

Here the spectator ions are $\mathrm{Na}^{+} \text { and } \mathrm{NO}_{3}^{-}$ hence the net ionic equation will be:

$\bold{A g^{+}(a q)+N O_{3}^{-}(a q) \rightarrow {AgI}(s)}$