Question

sodium metal crystallizes in a body centred cubic lattice with a unit cell edge of 4.29 the radius of sodium atom is approximately ?

Answer 1

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for BCC unit
⇛√3a = 4a

⇛r = √3/4 * a

⇛√3/4 * 4.29 Armstrong

⇛= 1.85 Armstrong

⇛ r = 1.85 Armstrong


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☬‌ ‌ ‌ ‌ ‌ THANKS! ‌@Brainlyconquerer ‌ ‌ ‌ ‌☬

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Answer 2

hey buddy!!

Here is your answer;

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⭐⭐⤵

In a body centered cubic lattice, atoms touch along the body diagonal of the cube . Thus

4r=√3a

or r=√3a/4

=(√3/4)(4.29A˙)=1.86A˙ (Answer)

➡hope this helps you deaR ✌✌✌.