Sodium reacts with excess oxygen to form sodium oxide. A student wants to prepare 1.24g of sodium oxide. While doing the calculations, he uses atomic number of sodium instead of atomic mass. What is the approximate percentage error in the mass of sodium oxide obtained due to this mistake?
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When burning sodium (Na) in oxygen (O2), you get sodium oxide (Na2O) and/or sodium peroxide (Na2O2). ... Since, sodium is a very reactive metal, it tends to react with oxygen to form sodium oxide but this is an unstable compound and soon reacts with hydrogen to form sodium hydroxide.
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