Question

Sodium surface is illuminated by ultraviolet and visible radiation successively and the stopping potential determined. This stopping potential is

Answer 1

Explanation:

ANSWER

λ for U.V is less than λ for visible light

ν for U.V is greather than ν for visible light

∴ potential is greater for U.V light.

as K.Eα

λ

1

Answer 2

Answer:

Explanation:

As per the equation

E = hv - Ф or evo = h∨ - Ф

We know that frequency of uv is greater than visible light

Stopping potential of uv is greater