Question

Soidum phosphate react with cobalt bromide solution

Answer 1

Answer:2Na3PO4(aq) + 3CoBr2(aq) ====> Co3(PO4)2(s) + 6NaBr(aq).

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Explanation:

Answer 2

Answer:

$\boxed{\ \ \ \ \ \ \boxed{\ \ \ \ \ \ 2Na_3PO_4+3CoBR_2\ \ \longrightarrow\ \ 6NaBR+Co_3(PO_4)_2\ \ \ \ \ \ }\ \ \ \ \ \ }$

Explanation:

⇒ Chemical formula of sodium phosphate = Na₃PO₄

• Oxidation number of sodium ion 'Na' = +1
• Oxidation number of phosphate ion 'PO₄' = -3

⇒ Chemical formula of cobalt bromide = CoBr₂

• Oxidation number of cobalt ion 'Co' = +2
• Oxidation number of bromide ion 'Br' = -1

⇒ Sodium phosphate react with cobalt bromide to get sodium bromide and cobalt phosphate.

• By comparing oxidation numbers of sodium and bromide ions, sodium bromide = Na₁Br₁ = NaBr
• By comparing oxidation numbers of cobalt and phosphate ions, cobalt phosphate = Co₃(PO₄)₂

⇒ Chemical equation,

$\boxed{\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Na_3PO_4+CoBR_2\ \ \longrightarrow\ \ NaBR+Co_3(PO_4)_2\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ }$

⇒ Balanced chemical equation,

$\boxed{\ \ \ \ \ \ \boxed{\ \ \ \ \ \ 2Na_3PO_4+3CoBR_2\ \ \longrightarrow\ \ 6NaBR+Co_3(PO_4)_2\ \ \ \ \ \ }\ \ \ \ \ \ }$