Question

(SOL): 1,2,3,4,5 and 6, determine how many different three-digit numbers can be formed, allowing repetitions.

Answer 1

Answer:

Step-by-step explanation:

The numbers we need should be of 3 digits,right?So we can take 3 blanks _ _ _

Now,let the no.s at each of these blanks be x,y and z- x y z

We have to determine how many three digits no can be formed and that to allowing repetitions, so x can be replaced by any number from 1 to 6 so there are 6 ways or 6 values of x.

In the same way y can also take no.s from 1 to 6 so there are 6 ways or 6 values of y.

Also, z can also take no.s from 1 to 6 so there are 6 ways or 6 values of z.

So total number of combinations become 6 x 6 x 6 = 216

So there are 216 three-digit numbers that can be formed from 1,2,3,4,5,6 ,allowing repetitions.

I hope this helps you