sol e the question present in the image and please explain in detail...
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sec⁶ x−tan⁶ x = 1 + 3 sec² x.tan² x
LHS
= sec⁶ x−tan⁶ x
= (sec² x)³ − (tan² x)³
= {sec² x − tan² x}³ + 3sec² x . tan² x(sec² x−tan² x)
= 1 + 3 sec² x.tan² x [ Since sec² x − tan² x=1]
= RHS
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