Question

Sol.
Given : PD and DQ are tangents of a circle with centre A
To prove seg DP = seg DQ
Construction - Draw radius AP and radius AQ
Complete the following proof
Proof: In APAD and AQAD
seg PAO
..... radii of the same circle
seg AD = seg AD
ZAPD = ZAQD = 90°​

Answer 1

Explanation:

Sol.

Given : PD and DQ are tangents of a circle with centre A

To prove DP = DQ

Construction - Draw radius AP and radius AQ and AD is joined.

Proof: In trianglePAD and triangleAQD,

AP=AQ (Radii of the same circle)

AD=AD (Common side)

angleAPD=angleAQD (90°)

Therefore, trianglePAD congruent to triangleAQD (R.H.S. congruence rule)

Therefore, DP=DQ

Hence,Proved..