Question

sol it ________________5​

Answer 1

Answer

Hope it will help you

Answer 2

Solution :

By using Mode Formula

$\boxed{ \tt Mode = l + \bigg( \dfrac{f_1 - f_0}{2f_1 -f_0 - f_2 } \bigg) \times h} \\ \\ \tt f_0 = 4 \\ \tt f_1 = 18 \\\tt f_2 = 9 \\\tt l = 4000 \\\tt h = 1000 \\ \\ \implies \tt4000 + \bigg( \dfrac{18 -4 }{2 \times 18 - 4 - 9} \bigg) \times 1000 \\ \\ \implies \tt4000 + \bigg( \dfrac{14}{36 - 13} \bigg) \times 1000 \\ \\ \implies \tt4000 + \dfrac{14000}{23} \\ \\ \implies \tt \dfrac{92000 + 14000}{23} \\ \\ \implies \tt \frac{106000}{23} \\ \\ \implies \tt4608.6 \\ \\ \large\boxed{ \tt \green{Mode = 4608.6 }}$