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sum of angle of triangle
a + b + C =180
b + C = 180 - a
LHS
sin (b + C)/2
sin ( 90 - a/2)
cos(a/2).
RHS
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Answer:
angle a + angle b + angle c=180
angle b + angle c= 180- angle a now sin180/2-angle a/2= 90-angle a/2 now then use Therom sin(90-90-angle a/2)=cos a/2 mark as brainlist
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