Question

Sol. () Let A : obtaining a total of at least 10. Then
A = {(6,4), (5, 5), (6,5), (4, 6), (5, 6), (6, 6)}
n (A) 6
(A)-6, n (S) = 36 : P (A) =
1
n(S) 36
36 6
1/​

Answer 1

n (A) 6

(A)-6, n (S) = 36 : P (A) =

1

n(S) 36

36 6

1/

gg.v

$1 < \tan( \cos( \sec( \infty ) ) )$