Question

sol
$(3x + 4)^2 + (3x - 2) ^{2} = (6x + 5)(3x - 2) + 12$
who ever solves it they are very great

Answer 1

we have

( 3x +4)^2 + ( 3 x-2)^2 = ( 6x +5 ) ( 3x -2 ) +12

=> 9x^2+ 6×4 + 16 + 9 x^2-12x +4 = 18x^2 -12x + 15x -10 +12

=> 18x^2 + 12 x +20 = 18 x^2 +3 x +2

=> 18 x^2 -18x^2 +12x -3x + 20 -2 =0

=> 9x +18 =0

=> x = -18 /9

=> then , x =- 2

hope this helps u

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