Question

sol this question completely on page plz​

Answer 1

Answer:

yes 3 , -1 , -1/3 is a zeroes of p(x)

Explanation:

p(x) = 3x³ - 5x² - 11x - 3

at x = 3

p(3) = 3(3)³ - 5(3)² - 11(3) - 3

= 3(27) - 5(9) - 33 - 3

= 81 - 45 - 36

= 81 - 81

= 0

p(3) = 0

then 3 is zero of polynomial

at x = -1

p(-1) = 3(-1)³ - 5(-1)² - 11(-1) - 3

= 3(-1) - 5(1) + 11 - 3

= - 3 - 5 + 11 - 3

= - 11 + 11

= 0

p(-1) = 0

then -1 is a zero of polynomial

at x = -1/3

p(-1/3) = 3(-1/3)³ - 5(-1/3)² - 11(-1/3) - 3

= 3(-1/27) - 5(1/9) + 11/3 - 3

= -1/9 - 5/9 + 11/3 - 3

= (-1 - 5 + 33 - 27)/9

= ( - 33 + 33)/9

= 0/9

= 0

p(-1/3) = 0

so -1/3 is a zero of polynomial