Math, asked by Anonymous, 5 months ago

Solbe amd check
5(6x-1) = 3(8+x)-2

Answers

Answered by Asterinn
5

➡️ 5(6x-1) = 3(8+x)-2

➡️ 30x-5 = 24+3x-2

➡️ 30x-3x = 24-2+5

➡️ 27x = 27

➡️ x = (27) / (27)

➡️ x = 1

Therefore , Value of x = 1

Now we will check if our answer is correct or not.

To check answer x = 1 in 5(6x-1) = 3(8+x)-2.

LHS : 5(6x-1)

➡️30x-5

put x = 1

➡️30-5 = 25

RHS : 3(8+x)-2

➡️24+3x-2

➡️22+3x

put x = 1

➡️22+3

➡️25

Therefore, LHS = RHS

Hence verified

Answer is correct.

Answered by iTzShInNy
13

Answer:

  \huge\sf ➲{\underline{ \underline \color{darkgreen}{question}}} \\  \\  \sf{solve \: and \: check✔}   \huge\bold\blue ⇩ \\  \\ \tt  \red♡5(6x - 1) = 3(8 + x) - 2  \red♡ \\  \\   \huge\sf ➲{\underline{ \underline \color{darkgreen}{solution}}} \\  \\  \\   \large \tt\blue➦ \: 5(6x - 1) = 3(8 + x) - 2 \\  \\ \large \tt\blue➦  \: 30x - 5 = 24 + 3x - 2 \\  \\ \large \tt\blue➦  \: 30x - 3x = 24 - 2 + 5 \\  \\  \large \tt\blue➦  \: 27x = 22 + 5 \\  \\  \large \tt\blue➦  \: 27x = 27 \\  \\ \large \tt\blue➦  \: x =   \cancel\frac{27} {27}^{1} \\  \\ \large \tt\blue➦  \: x = 1 \\  \\  \\   \huge\sf ➲{\underline{ \underline \color{darkgreen}{checking}}} \\  \\   \large\bf \red{ \: let \: x  }= 1 \\  \\  \\ \large \tt\blue➦ 5(6x - 1) = 3(8 + x) - 2 \\  \\ \large \tt\blue➦ 5(6 \times 1 - 1) = 3(8 + 1) - 2 \\  \\ \large \tt\blue➦ 5(6 - 1) = 24 + 3 - 2 \\  \\ \large \tt\blue➦ 30 - 5 = 27 - 2 \\  \\ \large \tt\blue➦ 25 = 25 \\  \\  \\   \large\therefore\sf LHS = RHS

 \\ \\

Link➺

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