Question

solbe this fast plz plz​

Answer 1

Answer:

mass of NH3 produced is 85 g

Explanation:

here firstly we find the limiting reagent ( the reactant which is present in less amount than the other reactant ) by finding moles .

for N2= given mass / molar mass / stochiometric cofficient

        =  60/ 14 /1

         = 4'28

for H2 = 15 / 2 /3

          = 15/ 6

           = 2.5

so H2 is the limiting reagent

now moles of H2 is equal to that of ammonia

2.5 = mass of ammonia formed/ molar mass of NH3 / 2

2.5 = m / 17/2

2.5 = m/ 34

m = 85