Question

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Answer 1

Answer:x2+(a−b)x+(1−a−b)=0, a,b∈Rx2+(a−b)x+(1−a−b)=0, a,b∈R . Find the least integral value of ‘a’ for which both roots of the equation are real and unequal (∀b∈R)(∀b∈R).

Explanation: