sole by using quadratic formula
x2+1/x=3 x is not =0
root 3 square +10x- 8root3=0
x2-x+1=0
x2-x-a[a+1}=0
plz friends help me i am asking help bcoz we have a bad faculty in oys school am blak
raoatchut191:
sure
I'd the first Q (x^2+1)/x=3 or the one which you have typed?
here b means the coefficient of x ,a means coefficient of x^2 and c means constant.now find b^2-4ac ,find whether its values are less than zero or greater than zero or equal to zero
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ax^2+bx+c=0 is termed as quadratic equation for a not being 0
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ax²+bx+c=0 is a quadratic equation for x≠0
Here, x=(-b±√{b²-4ac})/2a
When you substitute the corresponding values you get the answers.
1.x²-3x+1=0 here, a=1 b=-3 c=1 putting these values in the above formula you get x=(3±√5)/2.
2.a=√3 b=10 c=-8√3 hence x=11/2 or -17/2
3.x=(1±√-3)/2
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