Question

Sole the equation 4a^2−12a−(a−3)=0

Answer 1

Here's your answer:-

_________________________

4a^2-12a-(a-3)=0

4a^2-12a-a+3=0

4a^2-13a+3=0

4a^2-12a-a+3=0

4a(a-3)-1(a-3)=0

(a-3)(4a-1)=0

therefore-

a=3

a=1/4

**I HOPE IT WILL HELP YOU**

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Answer 2

hey! your answer

4a^2-12a-a+3= 0

4a^2-13a+3=0

4a^2-12a-a+3=0

4a(a-3)-1(a-3)=0

(a-3)(4a-1)=0

a-3=0

a=3

or

4a-1=0

4a=1

a=1/4

hope that it will help you