Question

Sole this trigonometry problem.

Answer 1

Answer:

,

Step-by-step explanation:

I hope my answer will be helpful for you

Answer 2

This is a question of trigonometric ratios.

Note: ∅ = theta

In ∆ABC let angle A = ∅

We know that ,

cot∅ = $\bf{\frac{base}{perpendicular}}$

In ∆ABC with respect to cot∅ ,

Perpendicular = 9

Perpendicular = 9 Base = 40

So , now we will apply pythogaurous theorem in ∆ABC.

(Hypotenuse)² = (Perpendicular)² + (Base)²

AC² = AB² + BC²

AC² = (40)² + (9)²

AC² = 1600 + 81

AC² = 1681

AC = √1681

AC = 41

Now , we will have to find sin∅ and cosec∅

we know that ,

sin∅ = $\bf{\frac{perpendicular}{hypotenuse}}$

sin∅ = $\bf{\frac{9}{41}}$

Also we have to find cosec∅,

we know that,

cosec∅ = $\bf{\frac{hypotenuse}{perpendicular}}$

cosec∅ = $\bf{\frac{41}{9}}$