Question

sole with full process please​

Answer 1

Given Question:-

$\dfrac{2}{3}$ of a number is 20 less than the original number. Find the number.

Solution:-

Let us assume that the original number = x

Then,

According to question

x - $(\dfrac{2x}{3})$ = 20

⟹ $\dfrac{3x - 2x}{3}$ = 20

⟹ $\dfrac{x}{3}$ = 20

⟹ x = 20 × 3

⟹ x = 60

Verification:-

x - $(\dfrac{2x}{3})$ = 20

⟹ 60 - $(\dfrac{2\times 60}{3})$ = 20

⟹ 60 - $\dfrac{120}{3}$ = 20

⟹ $\dfrac{180 - 120}{3}$ = 20

⟹ $\dfrac{60}{3}$ = 20

⟹ 20 = 20

$\therefore$ L.H.S = R.H.S

Required Answer:-

Number = 60

Answer 2

Answer:

The original number is 60.

Step-by-step explanation:

Given that,

→ ⅔ of a number is 20 less than the original number.

Assuming the number as $x$

⅔ of x is $\frac{2x}{3}$

According to the question,

$\implies \: x - \frac{2x}{3} = 20$

$\implies \: \frac{3x - 2x}{3} = 20$

$\implies \: \frac{x}{3} = 20$

$\implies \: x = 3 \times 20$

$\implies \: x = 60$

Hence,

The number is 60 ans.