Question

solenoid 10cm long consist of 50 turns if a current of 2A passes through it the magnetic field at centre of solenoid​

Answer 1

Answer:

number of turns per unit length(n) =50/0.1

=500turns/metre

current(I)=2A

we have

B=μ0 nI

   =4π*10^(-7)*500*2

   =1.25*10^(-3) T

Answer 2

Answer:

4pi × 10-⁴ T

Explanation:

B=uo N I

> number of turns per metre

> 50/ 0.1 = 500 turns per metre

B= 4 pi x 10-⁷ x 500 x 2

B= 4 pi × 1000

B= 4 pi × 10-⁷ × 10 ³

B = 4 pi × 10 -⁴ T ANS