Question

solenoid of 2m lenghthas 1000 turns. inside the solenoid a conductor carrying current of 2 A is kept normal to its axis. the mass of the conductor is 3kg/m. find the current that has to be passed through the solenoid in order to suspend the wire inside the solenoid

Answer 1

Answer:

Given, length of solenoid; L=2m

Diameter d=3cm

CurrentI=5A

Number of turns per metre =

2

5×1000

n=2500m

−1

Using relation,

B=μ

0

nI

=4π×10

−7

×2500×5

B=1.57×10

−2

T