Solid aluminum metal reacts with solid diatomic iodine to form solid Al2I6.
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Answer:
a) 2KClO₃ → 2KCl + 3O₂
b) 2Al + 3I₂ → Al₂I₆
c) 2NaCl + H₂SO₄ → 2HCl + Na₂SO₄
d) H₃PO₄ + KOH → KH₂PO₄ + H₂O
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