solid ammonium carbamate dissociated according to the given reaction NH2COONH4----->2NH3(g)+CO2(g) total pressure of the gas is 5 atm. hence Kp is
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NH4COO2NH4(s)------->2NH3(g)+CO2(g)
at first 1 0 0
at equilibrium 1-x 2x x
mole fraction of gas
at equilibrium 0 2x/3x=2/3 x/3x=1/3
partial pressure 0 2P/3=2×5/3 P/3=5/3
=10/3
Kp= (pNH3)^2× (pCO2)= (10/3)^2×(5/3)= 500/27
at first 1 0 0
at equilibrium 1-x 2x x
mole fraction of gas
at equilibrium 0 2x/3x=2/3 x/3x=1/3
partial pressure 0 2P/3=2×5/3 P/3=5/3
=10/3
Kp= (pNH3)^2× (pCO2)= (10/3)^2×(5/3)= 500/27
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