Question

solid body of weight 9N is suspended by a string in water the tension in the string is 7.5N what is the volume of the body ?

Answer 1

Hello Dear.

Here is the answer---

Given ⇒
Weight of the body in air = 9 N.
Tension in the String = 7.5 N.
Since, Weight of the body in water = Tension in the string by which the body is suspended.

∴ Weight of the body in water = 7.5 N.

Loss in weight = Weight of the body in air - Weight of the body in Water.
∴ Loss in Weight = 9 - 7.5
∴ Loss in Weight = 1.5 N.
∴ Upthrust = 1.5 N.

Now,
Upthrust = Volume of the Water Displaced × Density of the Water × Acceleration due to gravity.

Density of the Water = 1000 kg/m³.
Acceleration due to gravity = 10 m/s².
Volume of the water displaced is equal to the volume of the Object.

Now,

1.5 = Volume of the water displaced × 1000 × 10
Volume of the water displaced = 1.5 × 10⁻⁴ m³


∴ Volume of the object = 1.5 × 10⁻⁴ m³.


Hope it helps.