Question

solid body weighs 1.80 Newton in air. its relative density is 8.5. how much will the body weight if placed in water?​

Answer 1

Answer:

1.589N

Explanation:

Weight in air = 1.80N  

Relative Density = 8.5 (Here, Relative Density = RD)  

RD = Weight of body in air / Upthrust

Therefore, Upthrust = Weight of body in air / RD

                                 = 1.80/ 8.5 =0.211N

Therefore, Weight of the body in water = 1.80 – 0.211

                                                                 = 1.589N