solid iron carbide and block of dimensions 4.4 metre 2.6 metre and 1 metres is cast into hollow cylindrical pipe of internal radius 30 metre and thickness 5 centimetre find the length of the pipe
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Volume of block =
4.4×2.6×1
= 11.44
Volume of block = Volume of outer cylinder- volume of inner cylinder
11.44 = π×35×35×h - π×30×30×h
11.44 = (22/7)×h (1225-900)
11.44×7/22 = h×325
52×7/100×325 = h
h = 0.0112 m
hope this helped you...... ..... ... !
4.4×2.6×1
= 11.44
Volume of block = Volume of outer cylinder- volume of inner cylinder
11.44 = π×35×35×h - π×30×30×h
11.44 = (22/7)×h (1225-900)
11.44×7/22 = h×325
52×7/100×325 = h
h = 0.0112 m
hope this helped you...... ..... ... !
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