Math, asked by Afxan7373, 6 months ago

solid is in the form of a cylinder of diameter 7 cm with hemispherical ends.If the total length o fthe solid is 42 cm ,find the total surface area and the volume of the solid.

Answers

Answered by akinladeismail2025
1

Answer:

Step-by-step explanation:

Diameter= radius × 2

Therefore Radius = diameter/2

Radius r = 7/2

TSA cylinder + TSA of hemisphere = 2πr(r+h) + 3πr² = 2π×7/2(7/2+42) + 3π×(7/2)²

=7π{91/2} + 3π×49/4

=637π/2 + 147π/4

=π/2(637+1/2)

= π/2(1275/2)

:• the total surface area of the solid is 1275π/4.

Volume of the solid = volume of the cylinder + volume of hemisphere

Vol. = πr²h + ⅔πr³

= πr²{h + ⅔r}

π×49/4{42 + 7/3} = 49π/4{133/3}

=6517π/12

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