Question

solid is in the form of cone mounted on a hemisphere in such a way that the centre of the base of the hemisphere slant height of the cone is l and radius of the base of the cone is 1/2r where r is the radius of the hemisphere. prove that the total surface area of the solid is π/4(11r+2l)r sq. unit​

Answer 1

SOLUTION

Step-by-step explanation:

TSA of solid = TSA of cone - TSA of hemisphere

therefore ,

$\pi r (r+l)- 3\pi r^2\\\\\pi \frac{1}{2}r (\frac{1}{2}r +l)-3\pi r^2\\\\\frac{\pi r}{2}\left ( \frac{r+2l}{2} \right )-3\pi r^2\\\\\frac{\pi r^2 +2\pi rl }{4}-3\pi r^2\\\\\frac{\pi r^2 +2\pi rl- 12\pi r^2}{4}\\\\\frac{\pi}{4}r(11r-2l)$

hence proved

#Learn more :

A solid consist of a cone and a hemisphere which share common base. the cone has a base radius of 35cm. given that the volume of the cone is equal to 1 1/5 of the volume of the hemisphere find

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