solid is in the form of cylindrical with hemispherical end the total height of the solid is 58 and the diameter of the cylinder is 28 cm find the total surface area of the solid.
Answers
Answer:
Total Surface Area of Solid = 5104cm²
Step-by-step explanation:
r = 28/2 = 14cm
r = 28/2 = 14cmHeight of cylinder,h = 58-28 = 30cm
r = 28/2 = 14cmHeight of cylinder,h = 58-28 = 30cmTotal Surface Area of Solid
r = 28/2 = 14cmHeight of cylinder,h = 58-28 = 30cmTotal Surface Area of Solid= 2πr²+2πr²+2πrh = 4πr²+2πrh
r = 28/2 = 14cmHeight of cylinder,h = 58-28 = 30cmTotal Surface Area of Solid= 2πr²+2πr²+2πrh = 4πr²+2πrh= 2πr(2r+h) = 2×(22/7)×14(28+30)
r = 28/2 = 14cmHeight of cylinder,h = 58-28 = 30cmTotal Surface Area of Solid= 2πr²+2πr²+2πrh = 4πr²+2πrh= 2πr(2r+h) = 2×(22/7)×14(28+30)= 2×22×2×58
r = 28/2 = 14cmHeight of cylinder,h = 58-28 = 30cmTotal Surface Area of Solid= 2πr²+2πr²+2πrh = 4πr²+2πrh= 2πr(2r+h) = 2×(22/7)×14(28+30)= 2×22×2×58=5104cm²