Question

Solid magnesium has a specific heat of 1.01 J/g°C. How much heat is given off by a 11.4 gram sample of magnesium when it cools from 81.3°C to 40.3°C?

Answer 1

Answer:

Based on what you've given me, we have the mass of the sample (m), the specific heat (c), and the change in temperature

Δ

T

.

I should also add that "m" isn't limited to just water, it can be the mass of almost any substance. Also,

Δ

T

is

−

20

o

C

because the change in temperature is always final temperature- initial temperature

(

50

o

C

−

70

o

C

).

All of the variables have good units, so we just have to multiply all of the given values together to obtain Q (energy transferred).

Q

=

20.0

g

×

1.01

J

g

×

o

C

×

−

20

o

C