Solid magnesium has a specific heat of 1.01 J/g°C. How much heat is given off by a 11.4 gram sample of magnesium when it cools from 81.3°C to 40.3°C?
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Answer:
Based on what you've given me, we have the mass of the sample (m), the specific heat (c), and the change in temperature
Δ
T
.
I should also add that "m" isn't limited to just water, it can be the mass of almost any substance. Also,
Δ
T
is
−
20
o
C
because the change in temperature is always final temperature- initial temperature
(
50
o
C
−
70
o
C
).
All of the variables have good units, so we just have to multiply all of the given values together to obtain Q (energy transferred).
Q
=
20.0
g
×
1.01
J
g
×
o
C
×
−
20
o
C
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