Question

Solid spheres of diameter 4cm are dropped into a cylindrical beaker containing some water and are fully submerged if the diameter of the beaker is 12cm and the water raises 24cm find the number of solid spheres dropped in the water

Answer 1

let n number of solid sphere dropped in beaker
volume of n solid sphere =volume of water level increase in beaker

n x 4/3 pi.r^3=pi.R^2.h
n x 4/3 x (2)^3=(6)^2 x (24)
n x 4/3 x 8 =36 x 24
n=36 x 24 x 3 /4 x 8
=9 x 3 x 3 =81
hence 81 solids dropped in beaker

Answer 2

let n number of solid sphere dropped in beaker

volume of n solid sphere =volume of water level increase in beaker

n x 4/3 pi.r^3=pi.R^2.h

n x 4/3 x (2)^3=(6)^2 x (24)

n x 4/3 x 8 =36 x 24

n=36 x 24 x 3 /4 x 8

=9 x 3 x 3 =81

hence 81 solids dropped in beaker