Question

Solubility of Agbr will be minimum in :-
1). Pure water
2) 0.1 CaBr2
3) 0.1M NaBr
4) 0.1MAgNo3

Answer 1

in pure water because let x be the(ag+) br- in a saturated solution. therefore ksp=(ag+)(br-)=(x)(x)=4.8×10_¹³=x²= x=√4.8×10_¹³=6.9×10^-7 molL

Answer 2

in pure water because let x be the(ag+) br- in a saturated solution