Solubility of ammouium choride at 293k is 37g.what mass of ammouium choride would be needed to make saturated solution in 10g of water at 293k
Answers
Explanation:
3.7 gram of Ammonium Chloride would be needed to make a saturated solution in 10 gram of water at 293 K
Explanation:
Solubility of Ammonium Chloride (NH₄Cl) at 293 K is 37 gram/100 mL
⇒ 37 gram of NH₄Cl is soluble in 100 mL of water
or, 37 gram of NH₄Cl is soluble in 100 gram of water
(∵ density of water = 1g/ml)
∵ In 100 gram of water amount of NH₄Cl soluble = 37 gram
∴ In 1 gram of water, amount of NH₄Cl soluble = 37/100 gram
= 0.37 gram
∴ In 10 gram of water, amount of NH₄Cl soluble = 0.37 × 10 = 3.7 gram
Therefore, 3.7 gram of Ammonium Chloride would be needed to make a saturated solution in 10 gram of water
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