solubility of baso4 in pure water is 4 into 10 power minus 5 m solubility of baso4 in 0.01 m bacl2 solution will be
Answers
solubility of barium sulphate in 0.01M of barium chloride is 1.6 × 10^-7
It has given that solubility of BaSO₄ in pure water is 4 × 10¯5 .
dissociation reaction of BaSO₄ is...
BaSO₄ ⇔Ba²⁺ + SO₄²¯
solubility constant, Ksp = [Ba²⁺][SO₄²¯]
= (4 × 10^-5)(4 × 10^-5)
= 1.6 × 10^-9
let s be the solubility of BaSO₄ in 0.01M BaCl₂ solution.
[Ba²⁺] = 0.01 + y ≈ y [ because y << 0.01 ]
[SO₄²¯] = 0.01
now solubility constant, Ksp = [Ba²⁺][SO₄¯]
⇒1.6 × 10^-9 = y × 0.01
⇒1.6 × 10^-9 = 0.01y
⇒y = 1.6 × 10^-7
therefore solubility of barium sulphate in 0.01M of barium chloride is 1.6 × 10^-7
Answer:
Explanatsolubility of barium sulphate in 0.01M of barium chloride is 1.6 × 10^-7
It has given that solubility of BaSO₄ in pure water is 4 × 10¯5 .
dissociation reaction of BaSO₄ is...
BaSO₄ ⇔Ba²⁺ + SO₄²¯
solubility constant, Ksp = [Ba²⁺][SO₄²¯]
= (4 × 10^-5)(4 × 10^-5)
= 1.6 × 10^-9
let s be the solubility of BaSO₄ in 0.01M BaCl₂ solution.
[Ba²⁺] = 0.01 + y ≈ y [ because y << 0.01 ]
[SO₄²¯] = 0.01
now solubility constant, Ksp = [Ba²⁺][SO₄¯]
⇒1.6 × 10^-9 = y × 0.01
⇒1.6 × 10^-9 = 0.01y
⇒y = 1.6 × 10^-7