Question

Solubility of h2s in water at stp is 0.195 m. Calculate kh

Answer 1

Answer:

Explanation:

Solubility of H₂S = 0.195 m

⇒ 0.195 moles of H₂S (solute) is dissolved in 1 kg of water (solvent)

Number of moles of solvent = 1000/18 = 55.55 moles

Mole fraction of H₂S, x = 0.195/(0.195 + 55.55)

                                      = 0.195/55.745

                                      = 0.0035

At STP, in terms of bar pressure = 0.987 bar

Hence, applying Henry's law

p = Kh.x

0.0987 = Kh x 0.0035

Kh = 0.987/0.0035

    = 282 bar

where