solubility of NaCl at 30 degree celsius is 25 gram if the solution is 300 gram then find out the mass of the solute present in the 30 degree Celsius
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Answered by
2
Given mass of NaOH=16 grams → Solute.
Given mass of water = 100 grams → Solvent
Solubility (in g/100g) =
solvent
Mass
×100
=
100
16
×100=16
Solubility of the solution is 16(g/100g)
Weight Percentage =
massofsolution
MassofSolute
×100
(100+16)g
16g
×100
Weight percentage =13.79%
Answered by
1
Solute.Given mass of water = 100 grams → SolventSolubility (in g/100g) = solventMass ×100= 10016 ×100=16Solubility of the solution is 16(g/100g)Weight Percentage = massofsolutionMassofSolute ×100(100+16)g16g ×100Weight percentage =13.79%
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