Question

solubility of NaCl at 30 degree celsius is 25 gram if the solution is 300 gram then find out the mass of the solute present in the 30 degree Celsius​

Answer 1

Given mass of NaOH=16 grams → Solute.

Given mass of water = 100 grams → Solvent

Solubility (in g/100g) =

solvent

Mass

×100

=

100

16

×100=16

Solubility of the solution is 16(g/100g)

Weight Percentage =

massofsolution

MassofSolute

×100

(100+16)g

16g

×100

Weight percentage =13.79%

Answer 2

Solute.Given mass of water = 100 grams → SolventSolubility (in g/100g) = solventMass ×100= 10016 ×100=16Solubility of the solution is 16(g/100g)Weight Percentage = massofsolutionMassofSolute ×100(100+16)g16g ×100Weight percentage =13.79%

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