Question

Solubility of nitrogen at 50 c is 2.5×10^-3 g dm at 760 mm pressure. What will be its solubility in mol dm^-3 at 10000mm and same temperature

Answer 1

Answer : The solubility will be, $2.349\times 10^{-3}mole/dm^3$

Solution :

First we have to calculate the solubility of nitrogen.

At 760 mm pressure the solubility of nitrogen = $2.5\times 10^{-3}g/dm^3$

At 10000 mm pressure the solubility of nitrogen = $\frac{10000mm}{760mm}\times (2.5\times 10^{-3}g/dm^3)$

At 10000 mm pressure the solubility of nitrogen = $32.89\times 10^{-3}g/dm^3$

Now we have to calculate the solubility of nitrogen in $mole/dm^3$

The solubility of nitrogen = $\frac{2.349\times 10^{-3}g/dm^3}{14g/mole}=2.349\times 10^{-3}g/dm^3$

Therefore, the solubility will be, $2.349\times 10^{-3}mole/dm^3$