Question

Solubility of potassium chloride at 50°C is 30 (in 70 g of water). Radha prepared a solution by adding 50 g of potassium chloride in 200 g of water at the same temperature and stored it in a beaker A. Raman took 75 g of solution from the beaker A and transferred it to beaker B. The amount of potassium chloride that should be added to the solution to make it a saturated solution (at the same temperature) is ......................

Plz answer correctly. I would appreciate if experts and ace answer my question...

Answer 1

HOPE IT HELPS!!! !!!!!!!!!!!!!!!!!!!

Answer 2

Hey mate,

◆ Answer-
x = 20 g

◆ Explaination-
Initially -
W1 = 50 g
W2 = 200 g
W = 50 + 200 = 250 g
C = 50/200 = 1/4

Later,
C = same = 1/4
W = 250-70 = 180 g
W1 = 180/4 = 45 g
W2 = 180 - 45 = 135 g

Let x be amount of potassium chloride to be added.
W1 = 45 + x
W2 = 135 g
W = 180 + x
C = 30/70 = 3/7

To calculate x,
C = W1 / W
3/7 = (45+x) / 135
405 = 315 + 7x
4x = 80
x = 20 g

Therefore, 20 g of potassium chloride is to be added.

Hope it helps...