Question

solubility product equation for 1:2 and 1:3 electrolytes​

Answer 1

Answer:

ii) For 1: 2 or 2 : 1 type salt-

Ex – Ag2 CO3 , Ag2CrO4, PbCl2, CaF2 etc.

AB2 ⇌ A2+ + 2 B–

S 2S

[A2+ ] = S mole / litre, [B–] = 2S

Ksp = [A2+ ] [B– ]2 = S x (2S)2

Ksp =4S3

S = 3√ Ksp /4

iii) For 1: 3 type salt-

Ex – Fe(OH)3 , Al(OH)3 , Cr(OH)3 etc.

AB3 ⇌ A3+ + 3 B–

S 3S

[A3+ ] = S mole / litre, [B–] = 3S

Ksp = [A3+ ] [B– ]3 = S x (3S)3

Ksp = 27 S 4

S = 4√ Ksp /27.

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Answer 2

Answer:

For 1: 2 or 2 : 1 type salt-

Ex – Ag2 CO3 , Ag2CrO4, PbCl2, CaF2 etc.

AB2 ⇌ A2+ + 2 B–

S 2S

[A2+ ] = S mole / litre, [B–] = 2S

Ksp = [A2+ ] [B– ]2 = S x (2S)2

Ksp =4S3

S = 3√ Ksp /4

iii) For 1: 3 type salt-

Ex – Fe(OH)3 , Al(OH)3 , Cr(OH)3 etc.

AB3 ⇌ A3+ + 3 B–

S 3S

[A3+ ] = S mole / litre, [B–] = 3S

Ksp = [A3+ ] [B– ]3 = S x (3S)3

Ksp = 27 S 4

S = 4√ Ksp /27······························

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Explanation: