Question

solubility product of BaCO3 is 2.6×10–⁹ estimate it's solubility?​

Answer 1

Explanation:

[CO32-] = 0.60 M

At equilibrium:

BaCO3 <----> Ba2+ + CO32-

s 0.6 + s

Ksp = [Ba2+][CO32-]

2.6*10^-9=(s)*(0.6+ s)

Since Ksp is small, s can be ignored as compared to 0.6

Above expression thus becomes:

2.6*10^-9=(s)*(0.6)

2.6*10^-9= (s) * 0.6

s = 4.333*10^-9 M

Answer: 4.3*10^-9 M

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