Question

Solubility product of silver chloride is 5.0 x 10-13. The quantity of potassium chloride to be added to
2.00 L of 1.00 M solution of silver nitrate to start the precipitation of AgCl is.
O 6.2*10-59
o 1.2*10-99
o 1.2*10-10 g
o 7.45*10-119​

Answer 1

Explanation:

Let the solubility of AgBr be S mollitre

−1

AgBr⇌Ag

+

+Br

−

Hence, [Ag

+

][Br

−

]=5×10

−13

[Ag

+

]=0.05

So [Br

−

]=10

−11

M.

It means 10

−11

moles of KBr moles in 1 litre of solution.

molecular mass of KBr=120gmol

−1

So 1.2×10

−9

g of KBr to be added to 1 litre of 0.05M solution of silver nitrate to start precipitation of AgBr.