Question

solue
factorization method
by
5y ²+13y
+8=0​

Answer 1

Answer:

5y^2+13y+8=0

= 5y^2+5y+8y+8=0

=5y(y+1) +8(y+1)=0

=(y+1) (5y+8)

Answer 2

Answer- The above question is from the chapter 'Quadratic Equations'.

Factorization in quadratic equations is a process of making factors of middle-term of a quadratic equation to find its roots.

Given question: Solve by factorization method- 5y ²+13y + 8 = 0​

Solution: In 5y ²+13y + 8 = 0​

Sum = +13y

Product = 5 × 8 = 40

Factors= +8y , +5y

5y ² + 13y + 8 = 0​

5y ² + 5y + 8y + 8 = 0​

Taking out common,

5y(y + 1) + 8(y + 1) = 0

(y + 1) (5y + 8) = 0

Now, either y + 1 = 0

y = -1

Or 5y + 8 = 0

y = -8/5

So, y = -1, -8/5

∴ Roots of equation 5y ² + 13y + 8 = 0​ are -1 and -8/5.