Question

Solue the following: 1. In a circle with centre o op perpendicular AB, AB = 48cm Op=7cm, Find radius of a circle​

Answer 1

Answer:

Given: AB = 48, OP=7

OPB forms a right angled triangle. Apply Pythagoras Theorem on triangle OPB.

${op}^{2} + {pb}^{2} = {ob}^{2}$

Find PB. PB =(1/2) of AB.

So PB= 24.

Now putting PB and OP in above formula we get the answer.