solusi umum dari persamaan diferensial eksak (3x²+6xy)dx + (3x²+3y²)dy=0
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Answer:
d=0/x3+3x2y+y3
Step-by-step explanation:
Let's solve for d.
(3x2+6xy)(d)x+(3x2+3y2)(d)y=0
Step 1: Factor out variable d.
d(3x3+9x2y+3y3)=0
Step 2: Divide both sides by 3x^3+9x^2y+3y^3.
d(3x3+9x2y+3y3)/3x3+9x2y+3y3=0/3x3+9x2y+3y3
d=0/x3+3x2y+y3
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