Question

solution 2^x+2^1^-^x=3​

Answer 1

Answer:

Since it is in AP, the common difference is constant 

T2 - T1 = T3 - T2

\frac{1}{x + 3} - \frac{1}{x + 2} = \frac{1}{x + 5} - \frac{1}{x + 3}x+31−x+21=x+51−x+31 

(x+2-x-3)/(x+3)(x+2) = (x+3-x-5)/ (x+5)(x+3)

=> -1/ (x+2) = - 2 / (x+5)

=> - x - 5 = - 2x - 4

=> x = - 4 + 5

=> x = 1

Hope it will help you