Question

solution 200 g of a solution of KMNO4, labelled 10 % w/w will contain --------g of KMno4

Answer 1

Answer:

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Answer 2

Answer:

Explanation:

Given:  $200 g$ a  solution of $KmnO_{4}$ labeled $10$% w/w.

To Find: we have to find the amount of $KmnO_{4}$ present.

Concept: In addition to molarity, normalcy, or molality, solutions can be defined in terms of various concentrations. Sometimes, the relative percent concentration of a solute in a solution is used to describe solutions. Divide the mass of the solute by the mass of the solution (the solute and solvent together), and multiply by 100 to get the weight percentage of the solution. A solute's weight is given as a proportion of the weight of the entire solution in percent solutions. A raw ingredient employed in your recipe is referred to as a solute, whereas the term "solution" refers to the entire final mixture of your product.

The formula for percent by weight looks like this;

The percent by weight = $\frac{gram\cdot of solute}{100g \cdot ofsolution}$

Step 1

As we mentioned above the required formula so,

∵ $10%$% $=$ $\frac{(200g)}{x}$ ×%

so, $x$= $20g$

Hence, the $20g$ of $KmnO_{4}$ is present in the solution.

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